Showing posts with label Quadratic Equations. Show all posts
Showing posts with label Quadratic Equations. Show all posts

Thursday, May 28, 2015

What are the x-intercepts for the graph of y = x2 + 5x - 6?

We can use grouping to solve this quadratic because it can be factored.

x2+5x-6=0
x2 +6x-x-6=0
(x2+6x)-(x+6)=0
x(x+6)-(x+6)=0
(x-1)(x+6)=0

Next we can use the zero product property

x-1=0
x=1


or
x+6=0
x=-6

Monday, April 21, 2014

Friday, April 4, 2014

Thursday, April 3, 2014

Solve: (x+9)^2 + 11(x+9)+18=0

2*9=18 and 2+9=11, therefore...
(x+9)^2 + 11(x+9)+18=
((x+9)+2)((x+9)+9)=
(x+11)(x+18)=0
Solution:
{-11, -18}

Solve this equation: d^2-5d+6=0

d%5E2-5d%2B6=0

then...we'll use grouping to solve.

After looking at the factors 6 and 1 we notice that they don't quite work, so let's try 3 and 3:
d%5E2-5d%2B6=d%5E2-2d-3d%2B6=%28d%5E2-2d%29-%283d-6%29

Next we factor out the greatest common factors then we group them:
%28d%5E2-2d%29-%283d-6%29=d%28d-2%29-3%28d-2%29=%28d-3%29%28d-2%29

so that

%28d-3%29%28d-2%29=0

Finally, because of the zero product property we can see that
x=3 or x=2 

Saturday, November 23, 2013

3v%5E2-4v%2B1=0 
We'll use grouping - there are many ways...but grouping works well for this problem 
3v%5E2-3v-v%2B1=0 
3v%28v-1%29-%28v-1%29=0 
%283v-1%29%28v-1%29 
3v-1=0 
or 
v-1=0 
which leads to 
v=1/3 
or v=1

Thursday, August 22, 2013

Wednesday, August 21, 2013

the hypotenuse of a right triangle is 24 ft long. the length of one leg is 6 feet more than the other. find the length of the legs.

c=24 
Clearly the side we know the least about is the shortest so... 
a=x 
the length of one leg is 6 feet more than the other means... 
b=x+6 
So our equation is: 
x%5E2%2B%28x%2B6%29%5E2=24%5E2 
so here we go... 
x%5E2%2B%28x%5E2%2B12x%2B36%29=576 

2x%5E2%2B12x-540=0 
divide by 2... 
x%5E2%2B6x-270 

but this quadratic cannot be factored - so we use the quadratic formula 
x+=+%28-6+%2B-+sqrt%28+6%5E2-4%2A1%2A%28-270%29+%29%29%2F2+ 


From which the negative solution can be discarded (why?) 
therefore... 
x=3sqrt%2831%29-3 
and so... 
{{a=3sqrt(31)-3}}} 
{{b=3sqrt(31)+3}}} 
c=24

Tuesday, August 13, 2013

Saturday, August 3, 2013

Solve for x (x - 2)(x + 1) = 4

Notice that we cannot apply the zero product property...yet!

(x - 2)(x + 1) = 4 
x^2-x-2-4=0 
x^2-x-6=0 
(x-3)(x+2)=0 
x=3 or x=-2

Wednesday, July 17, 2013

solve: 8x^2-3=2x

8x^2-3=2x 
8x^2-2x-3=0 
8x^2+4x-6x-3=0 
(8x^2+4x)-(6x+3)=0 
4x(2x+1)-3(2x+1)=0 
(4x-3)(2x+1)=0 

x=3/4 or x=-1/2

Tuesday, May 7, 2013

one of my posts on Algebra.com


Solve: 231=7(x+8)x

231=7(x+8)x
the 231 seems large, so we look for a way to simplify - and it turns out to be a multiple of 7:

7%2A33=7%2A%28x%2B8%29x

using cancellation and rearranging terms we get the following:
x%5E2%2B8x=33

x%5E2%2B8x-33=0

Notice that 11+(-3)=8 and (11)(-3)=-33 so we'll use them in our grouping:

x%5E3%2B11x-3x-33=0


x%28x%2B11%29-3%28x%2B11%29=0

%28x-3%29%28x%2B11%29=0

which has solutions

x=3 and x=-11

:)