What value of x will you get by solving for x in 3/(x+a) = b/2?

Taking the reciprocal of both sides give us:

multiply both sides by 3:

subtract a from both sides:

How do I make 'b' the subject in this formula 1/r = 1/a + 1/b ?

B=(a-c)/( d-e) make e the subject of the formula

Solve for x

Solve for S

Solve for N

solve for x: x/a - 2x = c

 x/a - 2x = c

x(1/a-2)=c

x(1/a-2a/a)=c

x(1-2a)/a=c
a/(1-2a)x(1-2a)/a=ca/(1-2a)

x=c*a/(1-2a)

Solve s= h/m(v-u) for m

For literal equations we follow a kind of "reverse-PEMDAS" strategy: whatever was done to get an expression we undo.