(5x-7)/5=(6x+4)/2

Since this is a proportion, we'll cross multiply the solve for x:

:)

Find the excluded value(s) for the following expression : 4x/(x^2+x-6)

Rational expressions are defined whenever their denominators are real and non-zero, so...
x^2+x-6=(x+3)(x-2)=0
x=-3 or x=2

avoid {-3, 2}

me solve this problem: (3x+4)/(6x-2)=(x-5)/(2x+5)

  

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Solve for x

Solve for x

Solve: -4/(y+2)=-6+1/(y+1)

 

 

 
 

so y=-3/2 or y=-2/3

7 over 2 x + 1 over 2 x = 3x + 3 over 2 + 5 over 2 x

I believe you are describing: 
 
so that... 




 
 
 

leads to 

 
which has solutions: 

How would you solve; (x-5)/(x+6)=(x-3)/(x+4)

This is a proportion: 

 

 

 


 

 

 

:)

Find real solutions if any (4x-5)/(3-7x)=4

 

 
 

 

 

:)

What are intercepts, symmetry, asymptotes and graph of the equation y= 2x/(x^2-4)

 

Only 1 Intercept: (0,0) 
VA: x=2 and x=-2 
HA: y=0 
Axis of symmetry: x=0 

Graph: 

Solve the equation 3/x+2/9=1/3.

 

 

 

 

x=27 

:)

what is the value of x in 6/x = 7/(x+3)

 
then... 



We cross multiply because this is a proportion:
 




 

Solve: (1)/(x+7)+(2)/(x+3)=(-4)/(x^2+10x+21)

 

 

 

 


 

 

but this equation can never be true 

so our original equation has no solution 

:)