domain of f(x)=log(2*x-x^2)^1/2

2x-x^2=
x(2-x) 
so the domain is 
(-oo,0)U(2,oo)

the domain of the function f(x)=ln(2x+4) is?

Natural log is defined only for positive numbers so 
2x+4>0 
and so 

 
is the domain

Solve the exponential equation algebraically. Round the result to three decimal places. -14+3e^x=11

Solution: