Showing posts with label Function Evaluation. Show all posts
Showing posts with label Function Evaluation. Show all posts
Friday, June 5, 2015
Friday, May 29, 2015
Monday, August 26, 2013
Friday, July 5, 2013
Saturday, May 11, 2013
If h(n) = n^3-2n^2+5n+7 find h(0) and h(-1)
h(0) = (0)^3-2(0)^2+5(0)+7=7
and
h(-1) = (-1)^3-2(-1)^2+5(-1)+7 = -1-2-5+7=-1
:)
and
h(-1) = (-1)^3-2(-1)^2+5(-1)+7 = -1-2-5+7=-1
:)
Subscribe to:
Comments (Atom)



