Saturday, December 28, 2013

Solve: 3(4^2x)+5(4^x)-2=0

3%284%5E%282x%29%29%2B5%284%5Ex%29-2=0
u=4%5Ex
3u%5E2%2B5u-2=0
%283u-1%29%28u%2B2%29=0
u+2 is extraneous, assuming all solutions are to be real
3%2A4%5Ex=1
4%5Ex=1%2F3

Taking log base 4 of both sides...


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