Showing posts with label loga. Show all posts
Showing posts with label loga. Show all posts

Saturday, August 3, 2013

if 5^(x-1)=7^(1-x) then x =

5%5E%28x-1%29=7%5E%281-x%29 

5%5E%28x-1%29=7%5E%28-%28x-1%29%29 
5%5E%28x-1%29%2A7%5E%28x-1%29=1 
35%5E%28x-1%29=1 
35%5E%28x-1%29=35%5E0 
x-1=0 
x=1 

:)
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