what is the vertex: y = -x^2 - 4x - 3

Your Answer:

has a=-1, b=-4, c=-3
We can use the vertex formula:



and substitute to get y:




so our vertex is v(-2,1)

What is the axis of symmetry of f (x)=-x^2+4x+5 ?

Axis of symmetry x=2

Give the coordinates of the vertex for the graph of the equation: y=x^2+6x+9

In general...


v(-3,0)

but there is an easier way if we use the fact that it is a perfect square...


so that , 

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The graph of y = 2x^2 + 3x - 6 is drawn. Find the minimum value of y

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What is the minimum or maximum value of the quadratic function: f(x) ?

the actual value is





:)