Showing posts with label Absolute Value Inequalities. Show all posts
Showing posts with label Absolute Value Inequalities. Show all posts

Thursday, April 3, 2014

Monday, December 16, 2013

solve: -3+|2x+7| > 6

-3+|2x+7| > 6
-3+3+|2x+7| > 6+3
|2x+7| > 9
2x+7 > 9 or 2x+7 < -9
2x > 2 or 2x < -16
x > 1 or x < -8

Thursday, November 28, 2013

Friday, October 11, 2013

For what value of x is this inequality |x – 6|< - 8 true? Why?

for no value of x... 
|x – 6|< - 8 
has no solution because an absolute value of a real valued expression can never (by definition) be negative. Therefore it can never be less than -8

Tuesday, August 13, 2013

2+|4x-6|<12 

|4x+6|<10 

-10 < 4x+6 < 10 

-10+6 < 4x < 10+6 

-4/4 < x < 16/4 

-1 < x < 4

Friday, July 12, 2013

Find the interval notation for |2x-3|>-3 and its graph.

The statement 
|2x-3|>-3 
needs no work at all. An absolute value by definition is always greater than or equal to 0 (and therefore greater than any negative number) 
The graph is the entire number line and the interval is (-oo,oo). 


:)

Sunday, May 26, 2013

Solve 7+5|c|≤1-3|c|

%0D%0A7%2B5abs%28c%29%3C=1-3abs%28c%29%0D%0A 


%0D%0A5abs%28c%29%2B3abs%28c%29%3C=1-7%0D%0A 

%0D%0A8abs%28c%29%3C=-6%0D%0A 

W can stop immediately because the absolute value can never be negative so this inequality has no solution 

:)