Tuesday, August 13, 2013

How do I solve 5+2ln(x)=8

%0D%0A5%2B2ln%28x%29=8%0D%0A 


%0D%0A2ln%28x%29=8-5%0D%0A

%0D%0Aln%28x%29=1.5%0D%0A


%0D%0Ae%5Eln%28x%29=e%5E1.5%0D%0A


x=e%5E1.5%0D%0A
at

No comments:

Post a Comment